What are the solutions to the equation (x-4)^2=17 ?

The solutions to the equation (x-4)^2=17 are x=sqrt(17)+4,x=-sqrt(17)+4

Find the zeros of (x-4)^2=17

The zeros of (x-4)^2=17 are x=sqrt(17)+4,x=-sqrt(17)+4

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(x - 4)^{2} = 17

x = 17 + 4, x = - 17 + 4

Decimal Notation

x = 8.12310 \dots, x = - 0.12310 \dots

Solution steps

(x - 4)^{2} = 17

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 17 : x = 17 + 4

Solve

x - 4 = - 17 : x = - 17 + 4

The solutions to the quadratic equation are:

x = 17 + 4, x = - 17 + 4

(2 5^{\frac{3}{4}})^{2}

∣ x + 3 ∣ > 3

lo g_{30 e} (0.8) = - 0.04 d

- 3 u^{2} + 19 u + 14

8 - x^{2} = 7 x

What are the solutions to the equation (x-4)^2=17 ?
The solutions to the equation (x-4)^2=17 are x=sqrt(17)+4,x=-sqrt(17)+4
Find the zeros of (x-4)^2=17
The zeros of (x-4)^2=17 are x=sqrt(17)+4,x=-sqrt(17)+4