What is factor 16a^2+72ad+81d^2 ?

The solution to factor 16a^2+72ad+81d^2 is (4a+9d)^2

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factor 16a^2+72ad+81d^2

factor

16 a^{2} + 72 a d + 81 d^{2}

(4 a + 9 d)^{2}

Solution steps

16 a^{2} + 72 a d + 81 d^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

16 a^{2} = (4 a)^{2}

81 d^{2} = (9 d)^{2}

72 a d = 2 \cdot 4 a \cdot 9 d

= (4 a)^{2} + 2 \cdot 4 a \cdot 9 d + (9 d)^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(4 a)^{2} + 2 \cdot 4 a \cdot 9 d + (9 d)^{2} = (4 a + 9 d)^{2}

= (4 a + 9 d)^{2}

0 = x^{2} - 4 x - 4

(\frac{5}{2})^{- 2} \cdot \frac{25}{8}

1 - \frac{0.05}{2}

x^{2} + 12 x - 28 = 0

\frac{x ^{- 8}}{x ^{- 7}}

What is factor 16a^2+72ad+81d^2 ?
The solution to factor 16a^2+72ad+81d^2 is (4a+9d)^2