What is |p-0.53|<= 0.03 ?

The solution to |p-0.53|<= 0.03 is 0.5<= p<= 0.56

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|p-0.53|<= 0.03

∣ p - 0.53 ∣ \leq 0.03

0.5 \leq p \leq 0.56

Interval Notation

[0.5, 0.56]

Solution steps

∣ p - 0.53 ∣ \leq 0.03

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 0.03 \leq p - 0.53 \leq 0.03

p - 0.53 \geq - 0.03 and p - 0.53 \leq 0.03

p \geq 0.5 and p \leq 0.56

Merge Overlapping Intervals

0.5 \leq p \leq 0.56

∣ a + 9 ∣ + 2 \leq 6

16 a^{2} + 72 a d + 81 d^{2}

0 = x^{2} - 4 x - 4

(\frac{5}{2})^{- 2} \cdot \frac{25}{8}

1 - \frac{0.05}{2}