What are the solutions to the equation x^2-70x+200=0 ?

The solutions to the equation x^2-70x+200=0 are x=5(7+sqrt(41)),x=5(7-sqrt(41))

Find the zeros of x^2-70x+200=0

The zeros of x^2-70x+200=0 are x=5(7+sqrt(41)),x=5(7-sqrt(41))

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x^{2} - 70 x + 200 = 0

x = 5 (7 + 41), x = 5 (7 - 41)

Decimal Notation

x = 67.01562 \dots, x = 2.98437 \dots

Solution steps

x^{2} - 70 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 70 ) \pm ( - 70 ) ^{2} - 4 \cdot 1 \cdot 200}{2 \cdot 1}

(- 70)^{2} - 4 \cdot 1 \cdot 200 = 1041

x_{1, 2} = \frac{- ( - 70 ) \pm 10 41}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 70 ) + 10 41}{2 \cdot 1}, x_{2} = \frac{- ( - 70 ) - 10 41}{2 \cdot 1}

x = \frac{- ( - 70 ) + 10 41}{2 \cdot 1} : 5 (7 + 41)

x = \frac{- ( - 70 ) - 10 41}{2 \cdot 1} : 5 (7 - 41)

The solutions to the quadratic equation are:

x = 5 (7 + 41), x = 5 (7 - 41)

n^{2} + 13 n + 22 = 7

(\frac{( x + 2 )}{2}) + (\frac{( x - 3 )}{5}) = (\frac{6}{10}) + 12

5 x^{2} + 50 x y + 125 y^{2}

6 x - 2 \geq 9 x - 14

(6 x^{5})^{2}

What are the solutions to the equation x^2-70x+200=0 ?
The solutions to the equation x^2-70x+200=0 are x=5(7+sqrt(41)),x=5(7-sqrt(41))
Find the zeros of x^2-70x+200=0
The zeros of x^2-70x+200=0 are x=5(7+sqrt(41)),x=5(7-sqrt(41))