What is factor 4mn^2-4m^2n^2+m^3n^2 ?

The solution to factor 4mn^2-4m^2n^2+m^3n^2 is mn^2(m-2)^2

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factor 4mn^2-4m^2n^2+m^3n^2

factor

4 m n^{2} - 4 m^{2} n^{2} + m^{3} n^{2}

m n^{2} (m - 2)^{2}

Solution steps

4 m n^{2} - 4 m^{2} n^{2} + m^{3} n^{2}

Factor out common term

m n^{2} : m n^{2} (4 - 4 m + m^{2})

= m n^{2} (4 - 4 m + m^{2})

Factor

4 - 4 m + m^{2} : (m - 2) (m - 2)

= m n^{2} (m - 2) (m - 2)

Apply exponent rule:

aa = a^{2}

(m - 2) (m - 2) = (m - 2)^{2}

= m n^{2} (m - 2)^{2}

- x^{3} + 3 x^{2} - 2 x

x^{2} + 16 x + 28 = 0

\frac{1}{6} \leq \frac{1 - 6 t}{7} < \frac{6}{7}

2 x^{2} + 3 x^{3} + 4 x^{4}

3 - (4 x + 1) < 88 - 2 (x + 7)

What is factor 4mn^2-4m^2n^2+m^3n^2 ?
The solution to factor 4mn^2-4m^2n^2+m^3n^2 is mn^2(m-2)^2