What are the solutions to the equation x^2+16x+28=0 ?

The solutions to the equation x^2+16x+28=0 are x=-2,x=-14

Find the zeros of x^2+16x+28=0

The zeros of x^2+16x+28=0 are x=-2,x=-14

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x^{2} + 16 x + 28 = 0

x = - 2, x = - 14

Solution steps

x^{2} + 16 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 28 = 12

x_{1, 2} = \frac{- 16 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 12}{2 \cdot 1}, x_{2} = \frac{- 16 - 12}{2 \cdot 1}

x = \frac{- 16 + 12}{2 \cdot 1} : - 2

x = \frac{- 16 - 12}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = - 2, x = - 14

\frac{1}{6} \leq \frac{1 - 6 t}{7} < \frac{6}{7}

2 x^{2} + 3 x^{3} + 4 x^{4}

3 - (4 x + 1) < 88 - 2 (x + 7)

- 23 x > 23

\frac{7}{2}

What are the solutions to the equation x^2+16x+28=0 ?
The solutions to the equation x^2+16x+28=0 are x=-2,x=-14
Find the zeros of x^2+16x+28=0
The zeros of x^2+16x+28=0 are x=-2,x=-14