What are the solutions to the equation 5y^2-2y-3=0 ?

The solutions to the equation 5y^2-2y-3=0 are y=1,y=-3/5

Find the zeros of 5y^2-2y-3=0

The zeros of 5y^2-2y-3=0 are y=1,y=-3/5

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5 y^{2} - 2 y - 3 = 0

y = 1, y = - \frac{3}{5}

Solution steps

5 y^{2} - 2 y - 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 (- 3) = 8

y_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 5}, y_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 5}

y = \frac{- ( - 2 ) + 8}{2 \cdot 5} : 1

y = \frac{- ( - 2 ) - 8}{2 \cdot 5} : - \frac{3}{5}

The solutions to the quadratic equation are:

y = 1, y = - \frac{3}{5}

4 (x - 1)^{2} + \frac{1}{3} = \frac{7}{9}

x^{2} + 10 x - 600 = 0

8 + 8 p \geq - 152

\frac{15 m ^{- 7}}{3 ( m ^{- 2} ) ^{4}}

\frac{2}{2 ^{- 2}}

What are the solutions to the equation 5y^2-2y-3=0 ?
The solutions to the equation 5y^2-2y-3=0 are y=1,y=-3/5
Find the zeros of 5y^2-2y-3=0
The zeros of 5y^2-2y-3=0 are y=1,y=-3/5