What are the solutions to the equation 4(x-1)^2+1/3 = 7/9 ?

The solutions to the equation 4(x-1)^2+1/3 = 7/9 are x= 4/3 ,x= 2/3

Find the zeros of 4(x-1)^2+1/3 = 7/9

The zeros of 4(x-1)^2+1/3 = 7/9 are x= 4/3 ,x= 2/3

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4 (x - 1)^{2} + \frac{1}{3} = \frac{7}{9}

x = \frac{4}{3}, x = \frac{2}{3}

Solution steps

4 (x - 1)^{2} + \frac{1}{3} = \frac{7}{9}

Move

\frac{1}{3}

to the right side

4 (x - 1)^{2} = \frac{7}{9} - \frac{1}{3}

Simplify

\frac{7}{9} - \frac{1}{3} : \frac{4}{9}

4 (x - 1)^{2} = \frac{4}{9}

Divide both sides by

4

(x - 1)^{2} = \frac{1}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = \frac{1}{9} : x = \frac{4}{3}

Solve

x - 1 = - \frac{1}{9} : x = \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = \frac{2}{3}

x^{2} + 10 x - 600 = 0

8 + 8 p \geq - 152

\frac{15 m ^{- 7}}{3 ( m ^{- 2} ) ^{4}}

\frac{2}{2 ^{- 2}}

4 = 5 x

What are the solutions to the equation 4(x-1)^2+1/3 = 7/9 ?
The solutions to the equation 4(x-1)^2+1/3 = 7/9 are x= 4/3 ,x= 2/3
Find the zeros of 4(x-1)^2+1/3 = 7/9
The zeros of 4(x-1)^2+1/3 = 7/9 are x= 4/3 ,x= 2/3