What are the solutions to the equation x^2+10x-600=0 ?

The solutions to the equation x^2+10x-600=0 are x=20,x=-30

Find the zeros of x^2+10x-600=0

The zeros of x^2+10x-600=0 are x=20,x=-30

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x^{2} + 10 x - 600 = 0

x = 20, x = - 30

Solution steps

x^{2} + 10 x - 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 600 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 600) = 50

x_{1, 2} = \frac{- 10 \pm 50}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 50}{2 \cdot 1}, x_{2} = \frac{- 10 - 50}{2 \cdot 1}

x = \frac{- 10 + 50}{2 \cdot 1} : 20

x = \frac{- 10 - 50}{2 \cdot 1} : - 30

The solutions to the quadratic equation are:

x = 20, x = - 30

8 + 8 p \geq - 152

\frac{15 m ^{- 7}}{3 ( m ^{- 2} ) ^{4}}

\frac{2}{2 ^{- 2}}

4 = 5 x

x^{2} (\frac{1}{2} x^{- \frac{1}{2}})

What are the solutions to the equation x^2+10x-600=0 ?
The solutions to the equation x^2+10x-600=0 are x=20,x=-30
Find the zeros of x^2+10x-600=0
The zeros of x^2+10x-600=0 are x=20,x=-30