What are the solutions to the equation x^2+8x+9=0 ?

The solutions to the equation x^2+8x+9=0 are x=-4+sqrt(7),x=-4-sqrt(7)

Find the zeros of x^2+8x+9=0

The zeros of x^2+8x+9=0 are x=-4+sqrt(7),x=-4-sqrt(7)

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x^{2} + 8 x + 9 = 0

x = - 4 + 7, x = - 4 - 7

Decimal Notation

x = - 1.35424 \dots, x = - 6.64575 \dots

Solution steps

x^{2} + 8 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 9 = 27

x_{1, 2} = \frac{- 8 \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 7}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 7}{2 \cdot 1}

x = \frac{- 8 + 2 7}{2 \cdot 1} : - 4 + 7

x = \frac{- 8 - 2 7}{2 \cdot 1} : - 4 - 7

The solutions to the quadratic equation are:

x = - 4 + 7, x = - 4 - 7

8 v^{2} + 34 v - 30

z + 5 + 4 \leq 13

2 x y - 3 x - 4 y + 6

\frac{4}{3} \cdot π \cdot 7 5^{3}

3 ln (2) + ln (5) - ln (4)

What are the solutions to the equation x^2+8x+9=0 ?
The solutions to the equation x^2+8x+9=0 are x=-4+sqrt(7),x=-4-sqrt(7)
Find the zeros of x^2+8x+9=0
The zeros of x^2+8x+9=0 are x=-4+sqrt(7),x=-4-sqrt(7)