What is sqrt(z+5)+4<= 13 ?

The solution to sqrt(z+5)+4<= 13 is -5<= z<= 76

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sqrt(z+5)+4<= 13

z + 5 + 4 \leq 13

- 5 \leq z \leq 76

Interval Notation

[- 5, 76]

Solution steps

z + 5 + 4 \leq 13

Move

4

to the right side

z + 5 \leq 9

Square both sides

(z + 5)^{2} \leq 9^{2}

Simplify

z + 5 \leq 81

Move

5

to the right side

z \leq 76

Find singularity points

Find non-negative values for radicals:

z \geq - 5

Combine the intervals

z \leq 76 and z \geq - 5

Merge Overlapping Intervals

- 5 \leq z \leq 76

2 x y - 3 x - 4 y + 6

\frac{4}{3} \cdot π \cdot 7 5^{3}

3 ln (2) + ln (5) - ln (4)

4 x^{2} = 7 x + 2

- \frac{3 π}{2} + π