What are the solutions to the equation (3x+1)^2=7 ?

The solutions to the equation (3x+1)^2=7 are x=(sqrt(7)-1)/3 ,x=(-sqrt(7)-1)/3

Find the zeros of (3x+1)^2=7

The zeros of (3x+1)^2=7 are x=(sqrt(7)-1)/3 ,x=(-sqrt(7)-1)/3

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(3 x + 1)^{2} = 7

x = \frac{7 - 1}{3}, x = \frac{- 7 - 1}{3}

Solution steps

(3 x + 1)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 1 = 7 : x = \frac{7 - 1}{3}

Solve

3 x + 1 = - 7 : x = \frac{- 7 - 1}{3}

The solutions to the quadratic equation are:

x = \frac{7 - 1}{3}, x = \frac{- 7 - 1}{3}

\frac{6}{11} = \frac{y}{3}

9125

5 (2 x + 4) + 2 \leq 2 x + 2

6 x^{2} + x + 1 = 6 x

x^{4} + x^{2} + 1

What are the solutions to the equation (3x+1)^2=7 ?
The solutions to the equation (3x+1)^2=7 are x=(sqrt(7)-1)/3 ,x=(-sqrt(7)-1)/3
Find the zeros of (3x+1)^2=7
The zeros of (3x+1)^2=7 are x=(sqrt(7)-1)/3 ,x=(-sqrt(7)-1)/3