What are the solutions to the equation 6x^2+x+1=6x ?

The solutions to the equation 6x^2+x+1=6x are x= 1/2 ,x= 1/3

Find the zeros of 6x^2+x+1=6x

The zeros of 6x^2+x+1=6x are x= 1/2 ,x= 1/3

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6 x^{2} + x + 1 = 6 x

x = \frac{1}{2}, x = \frac{1}{3}

Solution steps

6 x^{2} + x + 1 = 6 x

Move

6 x

to the left side

6 x^{2} - 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 \cdot 1 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 6}

x = \frac{- ( - 5 ) + 1}{2 \cdot 6} : \frac{1}{2}

x = \frac{- ( - 5 ) - 1}{2 \cdot 6} : \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = \frac{1}{3}

x^{4} + x^{2} + 1

9 = 5 x + 27 + 4 x

3 n^{3} + 9 n^{2}

4 \cdot \frac{3}{4}

(i - 1)^{2}

What are the solutions to the equation 6x^2+x+1=6x ?
The solutions to the equation 6x^2+x+1=6x are x= 1/2 ,x= 1/3
Find the zeros of 6x^2+x+1=6x
The zeros of 6x^2+x+1=6x are x= 1/2 ,x= 1/3