4^{x+3}× 8^{2x-1}=sqrt(2)

Lösung

4^{x + 3} \cdot 8^{2 x - 1} = 2

x = - \frac{5}{16}

Dezimale

x = - 0.3125

Schritte zur Lösung

4^{x + 3} \cdot 8^{2 x - 1} = 2

Wende Exponentenregel an

2 x - 1 + 7 + 3 (2 x - 1) = \frac{1}{2}

Löse

2 x - 1 + 7 + 3 (2 x - 1) = \frac{1}{2} : x = - \frac{5}{16}

x = - \frac{5}{16}