3^{x+1}=8

Lösung

3^{x + 1} = 8

x = \frac{3 ln ( 2 )}{ln ( 3 )} - 1

Dezimale

x = 0.89278 \dots

Schritte zur Lösung

3^{x + 1} = 8

Wende Exponentenregel an

(x + 1) ln (3) = ln (8)

Löse

(x + 1) ln (3) = ln (8) : x = \frac{3 ln ( 2 )}{ln ( 3 )} - 1

x = \frac{3 ln ( 2 )}{ln ( 3 )} - 1

1 9^{x} = 0

2^{2 x} - 5 \cdot 2^{x + 2} + 64 = 0

7^{5 x - 2} = 343

4^{x} = \frac{1}{4}

4 (2^{2 x}) = 8 (2^{x}) - 4