4=b^2

Lösung

4 = b^{2}

b = 2, b = - 2

Schritte zur Lösung

4 = b^{2}

Tausche die Seiten

b^{2} = 4

Für

x^{2} = f (a)

sind die Lösungen

x = f (a), - f (a)

b = 4, b = - 4

4 = 2

- 4 = - 2

b = 2, b = - 2

x^{2} + 24 x - 140 = 0

6 x^{2} - 23 x = - 7

(2 x - 3)^{2} = 4 x + 5

(2 x + 5)^{2} + 1 = 0

so l v e f or x, f (x + 1) = 4 x^{2} + 2 x - 4