What are the solutions to the equation x^2=1^2+4^2+8^2 ?

The solutions to the equation x^2=1^2+4^2+8^2 are x=9,x=-9

Find the zeros of x^2=1^2+4^2+8^2

The zeros of x^2=1^2+4^2+8^2 are x=9,x=-9

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x^{2} = 1^{2} + 4^{2} + 8^{2}

x = 9, x = - 9

Solution steps

x^{2} = 1^{2} + 4^{2} + 8^{2}

Simplify

1^{2} + 4^{2} + 8^{2} : 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 81, x = - 81

81 = 9

- 81 = - 9

x = 9, x = - 9

3 x^{2} - 36 x + 843 = 0

x^{2} + 6 x = 4

\frac{3}{4} \cdot \frac{4}{5}

a^{2} + 6 a - 16

n^{2} = 81

What are the solutions to the equation x^2=1^2+4^2+8^2 ?
The solutions to the equation x^2=1^2+4^2+8^2 are x=9,x=-9
Find the zeros of x^2=1^2+4^2+8^2
The zeros of x^2=1^2+4^2+8^2 are x=9,x=-9