What are the solutions to the equation x^2+6x=4 ?

The solutions to the equation x^2+6x=4 are x=-3+sqrt(13),x=-3-sqrt(13)

Find the zeros of x^2+6x=4

The zeros of x^2+6x=4 are x=-3+sqrt(13),x=-3-sqrt(13)

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x^{2} + 6 x = 4

x = - 3 + 13, x = - 3 - 13

Solution steps

x^{2} + 6 x = 4

Move

4

to the left side

x^{2} + 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 4) = 213

x_{1, 2} = \frac{- 6 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 13}{2 \cdot 1}

x = \frac{- 6 + 2 13}{2 \cdot 1} : - 3 + 13

x = \frac{- 6 - 2 13}{2 \cdot 1} : - 3 - 13

The solutions to the quadratic equation are:

x = - 3 + 13, x = - 3 - 13

\frac{3}{4} \cdot \frac{4}{5}

a^{2} + 6 a - 16

n^{2} = 81

∣ x - 2 ∣ > 5

21 = \frac{x}{9}

What are the solutions to the equation x^2+6x=4 ?
The solutions to the equation x^2+6x=4 are x=-3+sqrt(13),x=-3-sqrt(13)
Find the zeros of x^2+6x=4
The zeros of x^2+6x=4 are x=-3+sqrt(13),x=-3-sqrt(13)