What are the solutions to the equation 3x^2-36x+843=0 ?

The solutions to the equation 3x^2-36x+843=0 are x=6+7sqrt(5)i,x=6-7sqrt(5)i

Find the zeros of 3x^2-36x+843=0

The zeros of 3x^2-36x+843=0 are x=6+7sqrt(5)i,x=6-7sqrt(5)i

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3 x^{2} - 36 x + 843 = 0

x = 6 + 75 i, x = 6 - 75 i

Solution steps

3 x^{2} - 36 x + 843 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 3 \cdot 843}{2 \cdot 3}

Simplify

(- 36)^{2} - 4 \cdot 3 \cdot 843 : 425 i

x_{1, 2} = \frac{- ( - 36 ) \pm 42 5 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 42 5 i}{2 \cdot 3}, x_{2} = \frac{- ( - 36 ) - 42 5 i}{2 \cdot 3}

x = \frac{- ( - 36 ) + 42 5 i}{2 \cdot 3} : 6 + 75 i

x = \frac{- ( - 36 ) - 42 5 i}{2 \cdot 3} : 6 - 75 i

The solutions to the quadratic equation are:

x = 6 + 75 i, x = 6 - 75 i

x^{2} + 6 x = 4

\frac{3}{4} \cdot \frac{4}{5}

a^{2} + 6 a - 16

n^{2} = 81

∣ x - 2 ∣ > 5

What are the solutions to the equation 3x^2-36x+843=0 ?
The solutions to the equation 3x^2-36x+843=0 are x=6+7sqrt(5)i,x=6-7sqrt(5)i
Find the zeros of 3x^2-36x+843=0
The zeros of 3x^2-36x+843=0 are x=6+7sqrt(5)i,x=6-7sqrt(5)i