What are the solutions to the equation x^2-x-10=2 ?

The solutions to the equation x^2-x-10=2 are x=4,x=-3

Find the zeros of x^2-x-10=2

The zeros of x^2-x-10=2 are x=4,x=-3

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x^{2} - x - 10 = 2

x = 4, x = - 3

Solution steps

x^{2} - x - 10 = 2

Move

2

to the left side

x^{2} - x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

x = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

x = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 4, x = - 3

199 - 2 x^{2} = x^{2} + 33 x + 28

6 m^{3} + 8 m^{2} + 9 m + 12

2 x^{2} - x - 3 < 0

x^{2} + (- \frac{2}{7})^{2} = 1

\frac{5 x + 5}{6} - 1 < \frac{19 x + 1}{3} - \frac{8 x + 1}{4}

What are the solutions to the equation x^2-x-10=2 ?
The solutions to the equation x^2-x-10=2 are x=4,x=-3
Find the zeros of x^2-x-10=2
The zeros of x^2-x-10=2 are x=4,x=-3