What are the solutions to the equation x^2-4x+60=0 ?

The solutions to the equation x^2-4x+60=0 are x=2+2sqrt(14)i,x=2-2sqrt(14)i

Find the zeros of x^2-4x+60=0

The zeros of x^2-4x+60=0 are x=2+2sqrt(14)i,x=2-2sqrt(14)i

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x^{2} - 4 x + 60 = 0

x = 2 + 214 i, x = 2 - 214 i

Solution steps

x^{2} - 4 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 60}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 60 : 414 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 14 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 14 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 14 i}{2 \cdot 1} : 2 + 214 i

x = \frac{- ( - 4 ) - 4 14 i}{2 \cdot 1} : 2 - 214 i

The solutions to the quadratic equation are:

x = 2 + 214 i, x = 2 - 214 i

4 y - 2 (6 - 3 y) = 18

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3 a - 24 = 9

- ∣ 2 x - 5 ∣ - 1 = - 2

\frac{e ^{5 i} - e ^{- 5 i}}{2 i}

What are the solutions to the equation x^2-4x+60=0 ?
The solutions to the equation x^2-4x+60=0 are x=2+2sqrt(14)i,x=2-2sqrt(14)i
Find the zeros of x^2-4x+60=0
The zeros of x^2-4x+60=0 are x=2+2sqrt(14)i,x=2-2sqrt(14)i