What are the solutions to the equation x^2-5x-14=0 ?

The solutions to the equation x^2-5x-14=0 are x=7,x=-2

Find the zeros of x^2-5x-14=0

The zeros of x^2-5x-14=0 are x=7,x=-2

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x^{2} - 5 x - 14 = 0

x = 7, x = - 2

Solution steps

x^{2} - 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

x = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

x = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 7, x = - 2

x^{2} - 4 x + 60 = 0

4 y - 2 (6 - 3 y) = 18

5 x^{3} + 30 x^{2} - 10 x

3 a - 24 = 9

- ∣ 2 x - 5 ∣ - 1 = - 2

What are the solutions to the equation x^2-5x-14=0 ?
The solutions to the equation x^2-5x-14=0 are x=7,x=-2
Find the zeros of x^2-5x-14=0
The zeros of x^2-5x-14=0 are x=7,x=-2