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x^2	x^{\msquare}	\log_{\msquare}	\sqrt{\square}	\nthroot[\msquare]{\square}	\le	\ge	\frac{\msquare}{\msquare}	\cdot	\div	x^{\circ}	\pi
\left(\square\right)^{'}	\frac{d}{dx}	\frac{\partial}{\partial x}	\int	\int_{\msquare}^{\msquare}	\lim	\sum	\infty	\theta	(f\:\circ\:g)	f(x)

\mathrm{simplify} \mathrm{solve\:for} \mathrm{expand} \mathrm{factor} \mathrm{rationalize}

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Frequently Asked Questions (FAQ)

How do you prove series value by induction step by step?
To prove the value of a series using induction follow the steps: Base case: Show that the formula for the series is true for the first term. Inductive hypothesis: Assume that the formula for the series is true for some arbitrary term, n. Inductive step: Using the inductive hypothesis, prove that the formula for the series is true for the next term, n+1. Conclusion: Since the base case and the inductive step are both true, it follows that the formula for the series is true for all terms.
What is the principle of induction?
The principle of induction is a basic principle of logic and mathematics that states that if a statement is true for the first term in a series, and if the statement is true for any term n assuming that it is true for the previous term n-1, then the statement is true for all terms in the series.
What is induction in calculus?
In calculus, induction is a method of proving that a statement is true for all values of a variable within a certain range. This is done by showing that the statement is true for the first term in the range, and then using the principle of mathematical induction to show that it is also true for all subsequent terms.
How do you prove divisibility by induction?
To prove divisibility by induction show that the statement is true for the first number in the series (base case). Then use the inductive hypothesis and assume that the statement is true for some arbitrary number, n. Using the inductive hypothesis, prove that the statement is true for the next number in the series, n+1. Since the base case is true and the inductive step shows that the statement is true for all subsequent numbers, the statement is true for all numbers in the series.

- \twostack{▭}{▭}	\lt	7	8	9	\div	AC
+ \twostack{▭}{▭}	\gt	4	5	6	\times	\square\frac{\square}{\square}
\times \twostack{▭}{▭}	\left(	1	2	3	-	x
▭\:\longdivision{▭}	\right)	.	0	=	+	y

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