What is the value of (pi^3)/3-cos(pi) ?

The value of (pi^3)/3-cos(pi) is (pi^3)/3+1

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(pi^3)/3-cos(pi)

\frac{π ^{3}}{3} - cos (π)

\frac{π ^{3}}{3} + 1

Decimal Notation

11.33542 \dots

Solution steps

\frac{π ^{3}}{3} - cos (π)

Use the following trivial identity:

cos (π) = (- 1)

cos (π)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= (- 1)

= \frac{π ^{3}}{3} - (- 1)

Simplify

= \frac{π ^{3}}{3} + 1

tan (1 5^{0})

20.9 + ((sin (\frac{π}{21} + \frac{e}{21}) \cdot 0.19 \cdot 21) - 0.21 + 1)

- 4 sin (- \frac{3 π}{4})

arccot (- \frac{9}{7})

sin (1 5^{\circ}) \cdot cos (1 5^{\circ})

What is the value of (pi^3)/3-cos(pi) ?
The value of (pi^3)/3-cos(pi) is (pi^3)/3+1