What is the value of (sin^2(pi))/2-(sin^2(0))/2 ?

The value of (sin^2(pi))/2-(sin^2(0))/2 is 0

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(sin^2(pi))/2-(sin^2(0))/2

\frac{sin ^{2} ( π )}{2} - \frac{sin ^{2} ( 0 )}{2}

0

Solution steps

\frac{sin ^{2} ( π )}{2} - \frac{sin ^{2} ( 0 )}{2}

Use the following trivial identity:

sin (π) = 0

sin (π)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= \frac{0 ^{2}}{2} - \frac{0 ^{2}}{2}

Simplify

= 0

arctan (1.19)

tan (10. 5^{\circ})

cot (arccos (\frac{8}{17}))

\frac{1 - cos ( 6 2 ^{\circ} )}{1 + cos ( 6 2 ^{\circ} )}

sin (\frac{π}{8}) cos (\frac{π}{8})

What is the value of (sin^2(pi))/2-(sin^2(0))/2 ?
The value of (sin^2(pi))/2-(sin^2(0))/2 is 0