What is the value of -sin((pi(2))/2) pi/2 ?

The value of -sin((pi(2))/2) pi/2 is 0

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-sin((pi(2))/2) pi/2

- sin (\frac{π ( 2 )}{2}) \frac{π}{2}

0

Solution steps

- sin (\frac{π ( 2 )}{2}) \frac{π}{2}

= - sin (\frac{π 2}{2}) \frac{π}{2}

Rewrite using trig identities:

sin (\frac{π 2}{2}) = 0

sin (\frac{π 2}{2})

Simplify

= sin (π)

Use the following trivial identity:

sin (π) = 0

sin (π)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= 0

= - 0 \cdot \frac{π}{2}

Simplify

= 0

- sec (\frac{π}{6}) + 2 sec^{3} (\frac{π}{6})

6 cos (\frac{5 π}{3})

sin (11.2 5^{\circ})

ln (sec (\frac{π}{6}) + tan (\frac{π}{6}))

sin (35 5^{\circ})

What is the value of -sin((pi(2))/2) pi/2 ?
The value of -sin((pi(2))/2) pi/2 is 0