What is the general solution for cos(2θ)=(sqrt(3))/2 ?

The general solution for cos(2θ)=(sqrt(3))/2 is θ= pi/(12)+pin,θ=(11pi)/(12)+pin

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cos(2θ)=(sqrt(3))/2

cos (2 θ) = \frac{3}{2}

θ = \frac{π}{12} + πn, θ = \frac{11 π}{12} + πn

Solution steps

cos (2 θ) = \frac{3}{2}

General solutions for

cos (2 θ) = \frac{3}{2}

2 θ = \frac{π}{6} + 2 πn, 2 θ = \frac{11 π}{6} + 2 πn

Solve

2 θ = \frac{π}{6} + 2 πn : θ = \frac{π}{12} + πn

Solve

2 θ = \frac{11 π}{6} + 2 πn : θ = \frac{11 π}{12} + πn

θ = \frac{π}{12} + πn, θ = \frac{11 π}{12} + πn

cos (2 x) = cos^{2} (x) - sin^{2} (x)

sin^{2} (x) + cos (2 x) - cos (x) = 0

arcsin (sin (\frac{3 π}{4}))

sin (2 θ) = 2 sin (θ) cos (θ)

sin (2 x) + sin (x) = 0

What is the general solution for cos(2θ)=(sqrt(3))/2 ?
The general solution for cos(2θ)=(sqrt(3))/2 is θ= pi/(12)+pin,θ=(11pi)/(12)+pin