What is the value of sec(-540) ?

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sec(-540)

sec (- 54 0^{\circ})

- 1

Solution steps

sec (- 54 0^{\circ})

Use the following property:

sec (- x) = sec (x)

sec (- 54 0^{\circ}) = sec (54 0^{\circ})

= sec (54 0^{\circ})

sec (54 0^{\circ}) = sec (18 0^{\circ})

sec (54 0^{\circ})

Rewrite

54 0^{\circ}

36 0^{\circ} + 18 0^{\circ}

= sec (36 0^{\circ} + 18 0^{\circ})

Apply the periodicity of

sec

sec (x + 36 0^{\circ}) = sec (x)

sec (36 0^{\circ} + 18 0^{\circ}) = sec (18 0^{\circ})

= sec (18 0^{\circ})

= sec (18 0^{\circ})

Use the following trivial identity:

sec (18 0^{\circ}) = (- 1)

sec (18 0^{\circ})

sec (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= (- 1)

= - 1

2 sin (37. 5^{\circ}) sin (97. 5^{\circ})

arcsin (sin (\frac{π}{7}))

2 cos (0) + sin (2 \cdot 0)

arccos (- \frac{3}{2})

- arcsin (1)