{
"query": {
"display": "$$\\left(\\sec\\left(\\frac{π}{4}\\right)\\right)^{2}$$",
"symbolab_question": "TRIG_EVALUATE#(\\sec(\\frac{π}{4}))^{2}"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Evaluate Functions",
"subTopic": "Simplified",
"default": "2",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\left(\\sec\\left(\\frac{π}{4}\\right)\\right)^{2}=2$$",
"input": "\\left(\\sec\\left(\\frac{π}{4}\\right)\\right)^{2}",
"steps": [
{
"type": "step",
"result": "=\\sec^{2}\\left(\\frac{π}{4}\\right)"
},
{
"type": "interim",
"title": "Use the following trivial identity:$${\\quad}\\sec\\left(\\frac{π}{4}\\right)=\\sqrt{2}$$",
"input": "\\sec\\left(\\frac{π}{4}\\right)",
"steps": [
{
"type": "step",
"primary": "$$\\sec\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\sec(x)&x&\\sec(x)\\\\\\hline 0&1&π&-1\\\\\\hline \\frac{π}{6}&\\frac{2\\sqrt{3}}{3}&\\frac{7π}{6}&-\\frac{2\\sqrt{3}}{3}\\\\\\hline \\frac{π}{4}&\\sqrt{2}&\\frac{5π}{4}&-\\sqrt{2}\\\\\\hline \\frac{π}{3}&2&\\frac{4π}{3}&-2\\\\\\hline \\frac{π}{2}&\\mathrm{Undefined}&\\frac{3π}{2}&\\mathrm{Undefined}\\\\\\hline \\frac{2π}{3}&-2&\\frac{5π}{3}&2\\\\\\hline \\frac{3π}{4}&-\\sqrt{2}&\\frac{7π}{4}&\\sqrt{2}\\\\\\hline \\frac{5π}{6}&-\\frac{2\\sqrt{3}}{3}&\\frac{11π}{6}&\\frac{2\\sqrt{3}}{3}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "=\\sqrt{2}"
}
],
"meta": {
"interimType": "Trig Trivial Angle Value Title 0Eq"
}
},
{
"type": "step",
"result": "=\\left(\\sqrt{2}\\right)^{2}"
},
{
"type": "interim",
"title": "Simplify $$\\left(\\sqrt{2}\\right)^{2}:{\\quad}2$$",
"input": "\\left(\\sqrt{2}\\right)^{2}",
"result": "=2",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt{a}=a^{\\frac{1}{2}}$$",
"result": "=\\left(2^{\\frac{1}{2}}\\right)^{2}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(a^{b}\\right)^{c}=a^{bc}$$",
"result": "=2^{\\frac{1}{2}\\cdot\\:2}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "interim",
"title": "$$\\frac{1}{2}\\cdot\\:2=1$$",
"input": "\\frac{1}{2}\\cdot\\:2",
"result": "=2",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:2}{2}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$2$$",
"result": "=1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l3vTdf410Ywhq1vZ0kzF8e30Fwl9QKPJxyO/TFRCb5Grju+5Z51e/ZZSD3gRHwjBE9/03SOiEv+BIHutWLr6nUfz18ijmoplMAomfJM9x8W1GdKgiNs+PolKvTuWzYk/"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7nFuqJhqdbE8vRlM8Q9mP1HyRHuGw7+tM5METTDj6vVH6JwS9po8Lx246e07g7nTMZEt3ZXAiqUE0HIXrrrezJHZKl2mV4AlztiApTAFigz1xilETpud1E7a+EPTJfjQEialcV/dI5TH4fXyp+ncwuA=="
}
}
],
"meta": {
"solvingClass": "Trig Evaluate",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Evaluate%20Functions",
"practiceTopic": "Evaluate Functions"
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
Solution steps
Use the following trivial identity:
periodicity table with cycle:
Simplify
Apply radical rule:
Apply exponent rule:
Multiply fractions:
Cancel the common factor:
Popular Examples
Frequently Asked Questions (FAQ)
What is the value of (sec(pi/4))^2 ?
The value of (sec(pi/4))^2 is 2