What is the general solution for sin^4(x)-sin^2(x)=0 ?

The general solution for sin^4(x)-sin^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin,x=2pin,x=pi+2pin

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sin^4(x)-sin^2(x)=0

sin^{4} (x) - sin^{2} (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

Solution steps

sin^{4} (x) - sin^{2} (x) = 0

Solve by substitution

sin (x) = 1, sin (x) = - 1, sin (x) = 0

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

(cos (t) - 4) (2 sin^{2} (t) - 1) = 0

sin (7 5^{\circ}) = \frac{x}{9}

i, 2 cos^{3} (x) + sin (x) + 1 = 2 sin^{2} (x)

t, tan (x) = csc^{2} (x) - 2

y, x y + 2 y = sin (x)

What is the general solution for sin^4(x)-sin^2(x)=0 ?
The general solution for sin^4(x)-sin^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin,x=2pin,x=pi+2pin