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Popular Trigonometry >

3sin^2(x)+2sin(x)cos^2(x/2)-sin(x)=0

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Solution

3sin2(x)+2sin(x)cos2(2x​)−sin(x)=0

Solution

x=2πn,x=π+2πn,x=−0.32175…+πn
+1
Degrees
x=0∘+360∘n,x=180∘+360∘n,x=−18.43494…∘+180∘n
Solution steps
3sin2(x)+2sin(x)cos2(2x​)−sin(x)=0
Factor 3sin2(x)+2sin(x)cos2(2x​)−sin(x):sin(x)(3sin(x)+2cos2(2x​)−1)
3sin2(x)+2sin(x)cos2(2x​)−sin(x)
Apply exponent rule: ab+c=abacsin2(x)=sin(x)sin(x)=3sin(x)sin(x)+2sin(x)cos2(2x​)−sin(x)
Factor out common term sin(x)=sin(x)(3sin(x)+2cos2(2x​)−1)
sin(x)(3sin(x)+2cos2(2x​)−1)=0
Solving each part separatelysin(x)=0or3sin(x)+2cos2(2x​)−1=0
sin(x)=0:x=2πn,x=π+2πn
sin(x)=0
General solutions for sin(x)=0
sin(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
x=0+2πn,x=π+2πn
x=0+2πn,x=π+2πn
Solve x=0+2πn:x=2πn
x=0+2πn
0+2πn=2πnx=2πn
x=2πn,x=π+2πn
3sin(x)+2cos2(2x​)−1=0:x=arctan(−31​)+πn
3sin(x)+2cos2(2x​)−1=0
Rewrite using trig identities
−1+2cos2(2x​)+3sin(x)
Use the Double Angle identity: 2cos2(x)−1=cos(2x)=3sin(x)+cos(2⋅2x​)
Multiply 2⋅2x​:x
2⋅2x​
Multiply fractions: a⋅cb​=ca⋅b​=2x⋅2​
Cancel the common factor: 2=x
=3sin(x)+cos(x)
Divide both sides by cos(x),cos(x)=0cos(x)cos(x)+3sin(x)​=cos(x)0​
Simplify1+cos(x)3sin(x)​=0
Use the basic trigonometric identity: cos(x)sin(x)​=tan(x)1+3tan(x)=0
1+3tan(x)=0
Move 1to the right side
1+3tan(x)=0
Subtract 1 from both sides1+3tan(x)−1=0−1
Simplify3tan(x)=−1
3tan(x)=−1
Divide both sides by 3
3tan(x)=−1
Divide both sides by 333tan(x)​=3−1​
Simplifytan(x)=−31​
tan(x)=−31​
Apply trig inverse properties
tan(x)=−31​
General solutions for tan(x)=−31​tan(x)=−a⇒x=arctan(−a)+πnx=arctan(−31​)+πn
x=arctan(−31​)+πn
Combine all the solutionsx=2πn,x=π+2πn,x=arctan(−31​)+πn
Show solutions in decimal formx=2πn,x=π+2πn,x=−0.32175…+πn

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Popular Examples

3tan^2(y)=5sec(y)-1((1-tan^2(a)))/((tan(a)))=2cot^2(a)cos(6x)=cos(2x)cot(x)cos(x)-sin(x)=1cos^4(x)+cos^3(x)-2=0

Frequently Asked Questions (FAQ)

  • What is the general solution for 3sin^2(x)+2sin(x)cos^2(x/2)-sin(x)=0 ?

    The general solution for 3sin^2(x)+2sin(x)cos^2(x/2)-sin(x)=0 is x=2pin,x=pi+2pin,x=-0.32175…+pin
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