What is the general solution for sin(x)sec(x)=2tan(x)-1 ?

The general solution for sin(x)sec(x)=2tan(x)-1 is x= pi/4+pin

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Popular Trigonometry >

sin(x)sec(x)=2tan(x)-1

Solution

sin (x) sec (x) = 2 tan (x) - 1

Solution

x = \frac{π}{4} + πn

Degrees

x = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

sin (x) sec (x) = 2 tan (x) - 1

Subtract

2 tan (x) - 1

from both sides

sin (x) sec (x) - 2 tan (x) + 1 = 0

Rewrite using trig identities

1 - 2 tan (x) + sec (x) sin (x)

sec (x) sin (x) = tan (x)

sec (x) sin (x)

Express with sin, cos

sec (x) sin (x)

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= \frac{1}{cos ( x )} sin (x)

Simplify

\frac{1}{cos ( x )} sin (x) : \frac{sin ( x )}{cos ( x )}

\frac{1}{cos ( x )} sin (x)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 sin ( x )}{cos ( x )}

Multiply:

1 \cdot sin (x) = sin (x)

= \frac{sin ( x )}{cos ( x )}

= \frac{sin ( x )}{cos ( x )}

= \frac{sin ( x )}{cos ( x )}

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

= tan (x)

= 1 - 2 tan (x) + tan (x)

Simplify

= 1 - tan (x)

1 - tan (x) = 0

Move

1

to the right side

1 - tan (x) = 0

Subtract

1

from both sides

1 - tan (x) - 1 = 0 - 1

Simplify

- tan (x) = - 1

- tan (x) = - 1

Divide both sides by

- 1

- tan (x) = - 1

Divide both sides by

- 1

\frac{- tan ( x )}{- 1} = \frac{- 1}{- 1}

Simplify

tan (x) = 1

tan (x) = 1

General solutions for

tan (x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

Graph

Popular Examples

sin(x)=sin(x+30)

cos^2(x)+7/12 cos(x)+1/12 =0

sec^{22}(x)=1-tan^2(x)

2sec(x)=1+cos(x)

sin^2(x)+cos(x)-cos^2(x)=0

Frequently Asked Questions (FAQ)

What is the general solution for sin(x)sec(x)=2tan(x)-1 ?
The general solution for sin(x)sec(x)=2tan(x)-1 is x= pi/4+pin