What is the general solution for solvefor y,(b)y=e^{5x}tan(x^2+2) ?

The general solution for solvefor y,(b)y=e^{5x}tan(x^2+2) is y=(e^{5x}tan(x^2+2))/b ;\quad b\ne 0

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solvefor y,(b)y=e^{5x}tan(x^2+2)

solve for

y, (b) y = e^{5 x} tan (x^{2} + 2)

y = \frac{e ^{5 x} tan ( x ^{2} + 2 )}{b}; b \neq = 0

Solution steps

(b) y = e^{5 x} tan (x^{2} + 2)

Divide both sides by

b; b \neq = 0

y = \frac{e ^{5 x} tan ( x ^{2} + 2 )}{b}; b \neq = 0

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\frac{tan ^{3} ( a )}{tan ( a )} = k

t, d^{2} \frac{u}{d ^{2}} v = tan^{2} (v) + 3

t, tan (27 0^{\circ} - a) = cot (a)

c, cos (x) + sin (3 x) = cos (2 x)

What is the general solution for solvefor y,(b)y=e^{5x}tan(x^2+2) ?
The general solution for solvefor y,(b)y=e^{5x}tan(x^2+2) is y=(e^{5x}tan(x^2+2))/b ;\quad b\ne 0