What is the general solution for (tan^3(a))/(tan(a))=k ?

The general solution for (tan^3(a))/(tan(a))=k is k=tan^2(a)

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(tan^3(a))/(tan(a))=k

\frac{tan ^{3} ( a )}{tan ( a )} = k

k = tan^{2} (a)

Solution steps

\frac{tan ^{3} ( a )}{tan ( a )} = k

Switch sides

k = \frac{tan ^{3} ( a )}{tan ( a )}

Cancel the common factor:

tan (a)

k = tan^{2} (a)

t, d^{2} \frac{u}{d ^{2}} v = tan^{2} (v) + 3

t, tan (27 0^{\circ} - a) = cot (a)

c, cos (x) + sin (3 x) = cos (2 x)

c, \frac{1}{1} - cos (x) + \frac{1}{1} + cos (x) = 2 csc^{2} (x)

t, tan (x^{2}) + 3 = 2 sec^{2} (x)

What is the general solution for (tan^3(a))/(tan(a))=k ?
The general solution for (tan^3(a))/(tan(a))=k is k=tan^2(a)