What is the general solution for -sin^2(x)=-1 ?

The general solution for -sin^2(x)=-1 is x= pi/2+2pin,x=(3pi)/2+2pin

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-sin^2(x)=-1

- sin^{2} (x) = - 1

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

- sin^{2} (x) = - 1

Solve by substitution

sin (x) = 1, sin (x) = - 1

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

1 + tan (x) = sec^{2} (x)

4 cosh (2 x) = 4 + sinh (2 x)

∣ sin (x) ∣ = sin (x) + 2

sin (a) = 0.2315

\frac{1 ( cos ^{2} ( x ) )}{( 1 - sin ^{2} ( x ) )} = 0

What is the general solution for -sin^2(x)=-1 ?
The general solution for -sin^2(x)=-1 is x= pi/2+2pin,x=(3pi)/2+2pin