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Popular Trigonometry >

3cos(x)=2sec(x)-5

  • Pre Algebra
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Solution

3cos(x)=2sec(x)−5

Solution

x=1.23095…+2πn,x=2π−1.23095…+2πn
+1
Degrees
x=70.52877…∘+360∘n,x=289.47122…∘+360∘n
Solution steps
3cos(x)=2sec(x)−5
Subtract 2sec(x)−5 from both sides3cos(x)−2sec(x)+5=0
Rewrite using trig identities
5−2sec(x)+3cos(x)
Use the basic trigonometric identity: cos(x)=sec(x)1​=5−2sec(x)+3⋅sec(x)1​
3⋅sec(x)1​=sec(x)3​
3⋅sec(x)1​
Multiply fractions: a⋅cb​=ca⋅b​=sec(x)1⋅3​
Multiply the numbers: 1⋅3=3=sec(x)3​
=5−2sec(x)+sec(x)3​
5+sec(x)3​−2sec(x)=0
Solve by substitution
5+sec(x)3​−2sec(x)=0
Let: sec(x)=u5+u3​−2u=0
5+u3​−2u=0:u=−21​,u=3
5+u3​−2u=0
Multiply both sides by u
5+u3​−2u=0
Multiply both sides by u5u+u3​u−2uu=0⋅u
Simplify
5u+u3​u−2uu=0⋅u
Simplify u3​u:3
u3​u
Multiply fractions: a⋅cb​=ca⋅b​=u3u​
Cancel the common factor: u=3
Simplify −2uu:−2u2
−2uu
Apply exponent rule: ab⋅ac=ab+cuu=u1+1=−2u1+1
Add the numbers: 1+1=2=−2u2
Simplify 0⋅u:0
0⋅u
Apply rule 0⋅a=0=0
5u+3−2u2=0
5u+3−2u2=0
5u+3−2u2=0
Solve 5u+3−2u2=0:u=−21​,u=3
5u+3−2u2=0
Write in the standard form ax2+bx+c=0−2u2+5u+3=0
Solve with the quadratic formula
−2u2+5u+3=0
Quadratic Equation Formula:
For a=−2,b=5,c=3u1,2​=2(−2)−5±52−4(−2)⋅3​​
u1,2​=2(−2)−5±52−4(−2)⋅3​​
52−4(−2)⋅3​=7
52−4(−2)⋅3​
Apply rule −(−a)=a=52+4⋅2⋅3​
Multiply the numbers: 4⋅2⋅3=24=52+24​
52=25=25+24​
Add the numbers: 25+24=49=49​
Factor the number: 49=72=72​
Apply radical rule: nan​=a72​=7=7
u1,2​=2(−2)−5±7​
Separate the solutionsu1​=2(−2)−5+7​,u2​=2(−2)−5−7​
u=2(−2)−5+7​:−21​
2(−2)−5+7​
Remove parentheses: (−a)=−a=−2⋅2−5+7​
Add/Subtract the numbers: −5+7=2=−2⋅22​
Multiply the numbers: 2⋅2=4=−42​
Apply the fraction rule: −ba​=−ba​=−42​
Cancel the common factor: 2=−21​
u=2(−2)−5−7​:3
2(−2)−5−7​
Remove parentheses: (−a)=−a=−2⋅2−5−7​
Subtract the numbers: −5−7=−12=−2⋅2−12​
Multiply the numbers: 2⋅2=4=−4−12​
Apply the fraction rule: −b−a​=ba​=412​
Divide the numbers: 412​=3=3
The solutions to the quadratic equation are:u=−21​,u=3
u=−21​,u=3
Verify Solutions
Find undefined (singularity) points:u=0
Take the denominator(s) of 5+u3​−2u and compare to zero
u=0
The following points are undefinedu=0
Combine undefined points with solutions:
u=−21​,u=3
Substitute back u=sec(x)sec(x)=−21​,sec(x)=3
sec(x)=−21​,sec(x)=3
sec(x)=−21​:No Solution
sec(x)=−21​
sec(x)≤−1orsec(x)≥1NoSolution
sec(x)=3:x=arcsec(3)+2πn,x=2π−arcsec(3)+2πn
sec(x)=3
Apply trig inverse properties
sec(x)=3
General solutions for sec(x)=3sec(x)=a⇒x=arcsec(a)+2πn,x=2π−arcsec(a)+2πnx=arcsec(3)+2πn,x=2π−arcsec(3)+2πn
x=arcsec(3)+2πn,x=2π−arcsec(3)+2πn
Combine all the solutionsx=arcsec(3)+2πn,x=2π−arcsec(3)+2πn
Show solutions in decimal formx=1.23095…+2πn,x=2π−1.23095…+2πn

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Popular Examples

sin(a/2)=(1/2)sin(a)cos(x/2)=cos(x)+1d=(sin^4(x)-cos^2(x)+5)/(4*cos^2(x))2+cos^2(x)=5sin(x)tan^3(3x)-2sin^3(3x)=0

Frequently Asked Questions (FAQ)

  • What is the general solution for 3cos(x)=2sec(x)-5 ?

    The general solution for 3cos(x)=2sec(x)-5 is x=1.23095…+2pin,x=2pi-1.23095…+2pin
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