What is the general solution for sin^2(x)+3cos(x)-1=0 ?

The general solution for sin^2(x)+3cos(x)-1=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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sin^2(x)+3cos(x)-1=0

sin^{2} (x) + 3 cos (x) - 1 = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (x) + 3 cos (x) - 1 = 0

Rewrite using trig identities

- cos^{2} (x) + 3 cos (x) = 0

Solve by substitution

cos (x) = 0, cos (x) = 3

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (x) = 3 :

No Solution

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (\frac{3 x - 7}{2}) = 0

3 tan^{2} (x) = \frac{8}{sin ^{2} ( x )}

sin^{2} (x) + sin^{22} (x) + sin^{23} (x) = 1

5 sin (1.75 x) = 1.4

cos (a - 5) = 0.675

What is the general solution for sin^2(x)+3cos(x)-1=0 ?
The general solution for sin^2(x)+3cos(x)-1=0 is x= pi/2+2pin,x=(3pi)/2+2pin