What is the general solution for -sin^2(x)+2cos(x)-2=0 ?

The general solution for -sin^2(x)+2cos(x)-2=0 is x=2pin

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-sin^2(x)+2cos(x)-2=0

- sin^{2} (x) + 2 cos (x) - 2 = 0

x = 2 πn

Solution steps

- sin^{2} (x) + 2 cos (x) - 2 = 0

Rewrite using trig identities

- 3 + cos^{2} (x) + 2 cos (x) = 0

Solve by substitution

cos (x) = 1, cos (x) = - 3

cos (x) = 1 : x = 2 πn

cos (x) = - 3 :

No Solution

Combine all the solutions

x = 2 πn

sin (5 x - 1) = \frac{4}{5}

sin^{2} (x) = \frac{1}{36}

tan (x) = 31

sin^{4} (x) + cos^{2} (x) = 2

5 tan (x) = 15 cot (x)

What is the general solution for -sin^2(x)+2cos(x)-2=0 ?
The general solution for -sin^2(x)+2cos(x)-2=0 is x=2pin