What is the general solution for cos^2(x)+sin^2(x)=cos^5(x) ?

The general solution for cos^2(x)+sin^2(x)=cos^5(x) is x=2pin

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cos^2(x)+sin^2(x)=cos^5(x)

cos^{2} (x) + sin^{2} (x) = cos^{5} (x)

x = 2 πn

Solution steps

cos^{2} (x) + sin^{2} (x) = cos^{5} (x)

Rewrite using trig identities

1 = cos^{5} (x)

Switch sides

cos^{5} (x) = 1

For

x^{n} = f (a)

, n is odd, the solution is

cos (x) = 1

General solutions for

cos (x) = 1

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn

sin (x - 4 5^{5}) = \frac{( 2 )}{2}

\frac{sin ( x ) - 3 \cdot cos ( x )}{2} = 0

cos (\frac{1}{3 x}) = \frac{1}{3}

arctan (1 + x) + arctan (1 - x) = arctan (\frac{1}{2})

- 4 cos^{2} (x) = 0

What is the general solution for cos^2(x)+sin^2(x)=cos^5(x) ?
The general solution for cos^2(x)+sin^2(x)=cos^5(x) is x=2pin