What is the general solution for cos^4(x)=cos^{23}(x) ?

The general solution for cos^4(x)=cos^{23}(x) is x= pi/2+2pin,x=(3pi)/2+2pin,x=2pin

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cos^4(x)=cos^{23}(x)

cos^{4} (x) = cos^{23} (x)

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2 πn

Solution steps

cos^{4} (x) = cos^{23} (x)

Solve by substitution

cos (x) = 0, cos (x) = 1

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (x) = 1 : x = 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2 πn

cos^{4} (x) + 2 cos^{2} (x) = 1

cos^{2} (x) + sin^{2} (x) = cos^{5} (x)

sin (x - 4 5^{5}) = \frac{( 2 )}{2}

\frac{sin ( x ) - 3 \cdot cos ( x )}{2} = 0

cos (\frac{1}{3 x}) = \frac{1}{3}

What is the general solution for cos^4(x)=cos^{23}(x) ?
The general solution for cos^4(x)=cos^{23}(x) is x= pi/2+2pin,x=(3pi)/2+2pin,x=2pin