What is the general solution for solvefor x,2sin(x)-cos(x)sin(x)=0 ?

The general solution for solvefor x,2sin(x)-cos(x)sin(x)=0 is x=2pin,x=pi+2pin

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solvefor x,2sin(x)-cos(x)sin(x)=0

solve for

x, 2 sin (x) - cos (x) sin (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

2 sin (x) - cos (x) sin (x) = 0

Factor

2 sin (x) - cos (x) sin (x) : - sin (x) (cos (x) - 2)

- sin (x) (cos (x) - 2) = 0

Solving each part separately

sin (x) = 0 or cos (x) - 2 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

cos (x) - 2 = 0 :

No Solution

Combine all the solutions

x = 2 πn, x = π + 2 πn

5 = 5 sin (4 θ)

cos (x) = \frac{cos ( x )}{csc ( x )}

cos (θ) = \frac{1}{1 ^{2} + ( 4 ) ^{2} + 8 ^{2}}

2 + 3 cot^{2} (x) - 3 csc (x) = 5

- 2 = - 2 + tan (θ)

What is the general solution for solvefor x,2sin(x)-cos(x)sin(x)=0 ?
The general solution for solvefor x,2sin(x)-cos(x)sin(x)=0 is x=2pin,x=pi+2pin