What is the general solution for 5=5sin(4θ) ?

The general solution for 5=5sin(4θ) is θ= pi/8+(pin)/2

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5=5sin(4θ)

5 = 5 sin (4 θ)

θ = \frac{π}{8} + \frac{πn}{2}

Solution steps

5 = 5 sin (4 θ)

Switch sides

5 sin (4 θ) = 5

Divide both sides by

5

sin (4 θ) = 1

General solutions for

sin (4 θ) = 1

4 θ = \frac{π}{2} + 2 πn

Solve

4 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{8} + \frac{πn}{2}

θ = \frac{π}{8} + \frac{πn}{2}

cos (x) = \frac{cos ( x )}{csc ( x )}

cos (θ) = \frac{1}{1 ^{2} + ( 4 ) ^{2} + 8 ^{2}}

2 + 3 cot^{2} (x) - 3 csc (x) = 5

- 2 = - 2 + tan (θ)

cos (A) = 0.65

What is the general solution for 5=5sin(4θ) ?
The general solution for 5=5sin(4θ) is θ= pi/8+(pin)/2