What is the general solution for cos(x)=(sqrt(2))/4 ?

The general solution for cos(x)=(sqrt(2))/4 is x=1.20942…+2pin,x=2pi-1.20942…+2pin

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cos(x)=(sqrt(2))/4

cos (x) = \frac{2}{4}

x = 1.20942 \dots + 2 πn, x = 2 π - 1.20942 \dots + 2 πn

Solution steps

cos (x) = \frac{2}{4}

Apply trig inverse properties

x = arccos (\frac{2}{4}) + 2 πn, x = 2 π - arccos (\frac{2}{4}) + 2 πn

Show solutions in decimal form

x = 1.20942 \dots + 2 πn, x = 2 π - 1.20942 \dots + 2 πn

sin (x) - sin (x) \cdot cos (x) = 0

1 - 1 tan^{2} (2 x) = sec^{2} (2 x)

10 tan (θ) - 4.9 (\frac{10}{13 cos ( θ )})^{2} = 0

1 - cos^{2} (θ) - 6959 cos (θ) = 0

(\frac{0.87 \cdot 1.04 \cdot sin ( 2 0 ^{\circ} - x )}{0.4}) = 0.05

What is the general solution for cos(x)=(sqrt(2))/4 ?
The general solution for cos(x)=(sqrt(2))/4 is x=1.20942…+2pin,x=2pi-1.20942…+2pin