What is the general solution for -sqrt(3)sin(2x)=cos(2x) ?

The general solution for -sqrt(3)sin(2x)=cos(2x) is x=(5pi}{12}+\frac{pin)/2

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-sqrt(3)sin(2x)=cos(2x)

- 3 sin (2 x) = cos (2 x)

x = \frac{5 π}{12} + \frac{πn}{2}

Solution steps

- 3 sin (2 x) = cos (2 x)

Rewrite using trig identities

- 3 tan (2 x) = 1

Divide both sides by

- 3

tan (2 x) = - \frac{3}{3}

General solutions for

tan (2 x) = - \frac{3}{3}

2 x = \frac{5 π}{6} + πn

Solve

2 x = \frac{5 π}{6} + πn : x = \frac{5 π}{12} + \frac{πn}{2}

x = \frac{5 π}{12} + \frac{πn}{2}

x, - sin (x) - cos (x) = 0

cos (2 θ) = (\frac{57}{11})

sin (x) cos (x^{2}) = sin (x), 0 \leq x \leq 2 π

θ, \frac{cos ( θ )}{sin ( θ )} = - \frac{π}{6}

tan (θ) = \frac{10}{- 5.32}

What is the general solution for -sqrt(3)sin(2x)=cos(2x) ?
The general solution for -sqrt(3)sin(2x)=cos(2x) is x=(5pi}{12}+\frac{pin)/2