What is the general solution for 3-6sin(2x)=0 ?

The general solution for 3-6sin(2x)=0 is x= pi/(12)+pin,x=(5pi)/(12)+pin

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3-6sin(2x)=0

3 - 6 sin (2 x) = 0

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

Solution steps

3 - 6 sin (2 x) = 0

Move

3

to the right side

- 6 sin (2 x) = - 3

Divide both sides by

- 6

sin (2 x) = \frac{1}{2}

General solutions for

sin (2 x) = \frac{1}{2}

2 x = \frac{π}{6} + 2 πn, 2 x = \frac{5 π}{6} + 2 πn

Solve

2 x = \frac{π}{6} + 2 πn : x = \frac{π}{12} + πn

Solve

2 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{12} + πn

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

\frac{1}{1} + cot^{2} (x) = sin^{2} (x)

x, 2 cos (x) = 2 cos (3 x)

sin (x) = 1 - 2 sin^{2} (x)

2 sin^{2} (t) - cos (t) - 1 = 0

4 cos^{2} (θ) = 1, 0 \leq θ < 2 π

What is the general solution for 3-6sin(2x)=0 ?
The general solution for 3-6sin(2x)=0 is x= pi/(12)+pin,x=(5pi)/(12)+pin