What is the general solution for (tan(x)-1)(sec(x)+1)=0 ?

The general solution for (tan(x)-1)(sec(x)+1)=0 is x= pi/4+pin,x=pi+2pin

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(tan(x)-1)(sec(x)+1)=0

(tan (x) - 1) (sec (x) + 1) = 0

x = \frac{π}{4} + πn, x = π + 2 πn

Solution steps

(tan (x) - 1) (sec (x) + 1) = 0

Solving each part separately

tan (x) - 1 = 0 or sec (x) + 1 = 0

tan (x) - 1 = 0 : x = \frac{π}{4} + πn

sec (x) + 1 = 0 : x = π + 2 πn

Combine all the solutions

x = \frac{π}{4} + πn, x = π + 2 πn

tan (θ) = \frac{9}{10}

tan (x) = \frac{3}{205}

sin (x) sin (2 x) = sin (3 x)

cot (x) = \frac{15}{8}

cos (θ) = \frac{- 5}{4}

What is the general solution for (tan(x)-1)(sec(x)+1)=0 ?
The general solution for (tan(x)-1)(sec(x)+1)=0 is x= pi/4+pin,x=pi+2pin