What is the general solution for -2sin(x)-2cos(x)=0 ?

The general solution for -2sin(x)-2cos(x)=0 is x=(3pi)/4+pin

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-2sin(x)-2cos(x)=0

- 2 sin (x) - 2 cos (x) = 0

x = \frac{3 π}{4} + πn

Solution steps

- 2 sin (x) - 2 cos (x) = 0

Rewrite using trig identities

- 2 tan (x) - 2 = 0

Move

2

to the right side

- 2 tan (x) = 2

Divide both sides by

- 2

tan (x) = - 1

General solutions for

tan (x) = - 1

x = \frac{3 π}{4} + πn

7 sin (b) = 5 sin (7 0^{\circ})

5 sin (x) + 2 cos^{2} (x) = 4

cos (\frac{1}{2} x) = - 1, y = 2

sin^{2} (a) = 2 sin^{2} (a) + 3

cos (x) = \frac{3}{3}, 0 \leq x \leq 2 π

What is the general solution for -2sin(x)-2cos(x)=0 ?
The general solution for -2sin(x)-2cos(x)=0 is x=(3pi)/4+pin