What is the general solution for cot(β)=(-sqrt(3))/3 ?

The general solution for cot(β)=(-sqrt(3))/3 is β=(2pi)/3+pin

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cot(β)=(-sqrt(3))/3

cot (β) = \frac{- 3}{3}

β = \frac{2 π}{3} + πn

Solution steps

cot (β) = \frac{- 3}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

cot (β) = - \frac{3}{3}

General solutions for

cot (β) = - \frac{3}{3}

β = \frac{2 π}{3} + πn

2 sin^{2} (3 x) - 3 cos (3 x) + 1 = 0

sin (θ) = \frac{15}{23}

3 sin^{2} (x) + 6 sin (x) - 11 = 7 sin (x) - 9

sin^{2} (a) = 2 sin (a)

sin (3 x - 50) cos (x) - cos (3 x - 50) sin (x) = 0, 0^{\circ} \leq x \leq 18 0^{\circ}

What is the general solution for cot(β)=(-sqrt(3))/3 ?
The general solution for cot(β)=(-sqrt(3))/3 is β=(2pi)/3+pin