What is the general solution for 3*cos(4θ)=0 ?

The general solution for 3*cos(4θ)=0 is θ= pi/8+(pin)/2 ,θ=(3pi)/8+(pin)/2

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3*cos(4θ)=0

3 \cdot cos (4 θ) = 0

θ = \frac{π}{8} + \frac{πn}{2}, θ = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

3 cos (4 θ) = 0

Divide both sides by

3

cos (4 θ) = 0

General solutions for

cos (4 θ) = 0

4 θ = \frac{π}{2} + 2 πn, 4 θ = \frac{3 π}{2} + 2 πn

Solve

4 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{8} + \frac{πn}{2}

Solve

4 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{8} + \frac{πn}{2}

θ = \frac{π}{8} + \frac{πn}{2}, θ = \frac{3 π}{8} + \frac{πn}{2}

5 tan (x) - 5 = 0

- 4 sin (x) + 3 cos (x) = 0

sin (x) - 1 = 0, sin (x) - 1 = 0

23 cos (2 x) = - 3

3 cos (x) + sin (x) = 1

What is the general solution for 3*cos(4θ)=0 ?
The general solution for 3*cos(4θ)=0 is θ= pi/8+(pin)/2 ,θ=(3pi)/8+(pin)/2