What is the general solution for 2sin(x)-sqrt(2)=0,0<= x<= 2pi ?

The general solution for 2sin(x)-sqrt(2)=0,0<= x<= 2pi is x= pi/4 ,x=(3pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin(x)-sqrt(2)=0,0<= x<= 2pi

2 sin (x) - 2 = 0, 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{3 π}{4}

Solution steps

2 sin (x) - 2 = 0, 0 \leq x \leq 2 π

Move

2

to the right side

2 sin (x) = 2

Divide both sides by

2

sin (x) = \frac{2}{2}

General solutions for

sin (x) = \frac{2}{2}

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{3 π}{4}

(2 sin (x) - 1) (sin (x) + 1) = 0

sin (A) = \frac{3}{4}

4 sin^{2} (x) + 42 cos (x) - 6 = 0

4 - 5 cos (x) = 4 + 3 sin (x)

\frac{tan ( θ ) cos ( θ )}{csc ( θ )} = sin (θ)

What is the general solution for 2sin(x)-sqrt(2)=0,0<= x<= 2pi ?
The general solution for 2sin(x)-sqrt(2)=0,0<= x<= 2pi is x= pi/4 ,x=(3pi)/4